Wanted- maths genius
Chr1s
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Starting to look a bit of a plank as I can't help my daughter with her maths homework If anyone can work it out and show workings I'd be extremely grateful, Thanks In advance
Patrick had 2/3 as many stickers as Quincy. After Patrick bought another 8 stickers and Quincy lost 5 stickers, Patrick then had 4/5 as many stickers as Quincy. Find the total number of stickers Patrick and Quincy had at first.
Patrick had 2/3 as many stickers as Quincy. After Patrick bought another 8 stickers and Quincy lost 5 stickers, Patrick then had 4/5 as many stickers as Quincy. Find the total number of stickers Patrick and Quincy had at first.
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Patrick 60 and Quincy 90
P + 8 = X And. Q - 5 = Y
Where P=2Q/3. And X=4Y/5
Substituting gives 2Q/3 + 8. = 4Y/5
Change denominator so it's the same for all ........ (10Q + 120)/15 = 12Y/15
X both sides by 15 and sub Y= Q-5........................ 150Q + 1800 = 180 (Q-5)
Do some maths here and eventually you'll get..........2700 = 180Q - 150Q
Therefore................................................................... Q = 90
and ..............................................................................P = 2x90/3 = 60
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