AAT Assessment 1 Task 1.7a

Hi,

Please can someone help with how to get the answers for the parts I've highlighted.

Sophie  • We need to establish what the limiting factor is first

Materials are 55000 kg and labour is 20000h

The Jackal takes 1 h to produce (6/6=1)
5000 units x 1h=5000h

Hyena take 2h (12/6=2), therefore 10000x2=20000h

The total hours required is 25000h

This is the limiting factor, so the contribution per limited factor is

For J 7/1h=7
Fir H 9/2h=4.5

Optimal units that can be produced will be

All of J as it has the highest contribution per limited factor, so 5000 units and whatever is left for H

5000 will take 5000h, so we have left 15000h/2h =7500 units of Hyena

AAT Level 2. 2018 Distinction
AAT Level 3. 2018 Distinction
AAT Level 4. 2019 FSLC 100% MABU 93% MADC 82% PDSY 80%
• dumutroba said:

We need to establish what the limiting factor is first

Materials are 55000 kg and labour is 20000h

The Jackal takes 1 h to produce (6/6=1)
5000 units x 1h=5000h

Hyena take 2h (12/6=2), therefore 10000x2=20000h

The total hours required is 25000h

This is the limiting factor, so the contribution per limited factor is

For J 7/1h=7
Fir H 9/2h=4.5

Optimal units that can be produced will be

All of J as it has the highest contribution per limited factor, so 5000 units and whatever is left for H

5000 will take 5000h, so we have left 15000h/2h =7500 units of Hyena

@dumutroba quick question why is it 10000 x 2 when Hyena sales demand is 11000?
• Misspelled. Is 11000x2h
AAT Level 2. 2018 Distinction
AAT Level 3. 2018 Distinction
AAT Level 4. 2019 FSLC 100% MABU 93% MADC 82% PDSY 80%