AAT Assessment 1 Task 1.7a

Hi,

Please can someone help with how to get the answers for the parts I've highlighted.

Thanks in advance.

Sophie



Comments

  • sophie_612sophie_612 LondonRegistered Posts: 102
    @dumutroba can you help?
  • dumutrobadumutroba AAT Student, AATQB Posts: 265
    We need to establish what the limiting factor is first

    Materials are 55000 kg and labour is 20000h

    The Jackal takes 1 h to produce (6/6=1)
    5000 units x 1h=5000h

    Hyena take 2h (12/6=2), therefore 10000x2=20000h

    The total hours required is 25000h

    This is the limiting factor, so the contribution per limited factor is

    For J 7/1h=7
    Fir H 9/2h=4.5

    Optimal units that can be produced will be

    All of J as it has the highest contribution per limited factor, so 5000 units and whatever is left for H

    5000 will take 5000h, so we have left 15000h/2h =7500 units of Hyena

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  • sophie_612sophie_612 LondonRegistered Posts: 102
    dumutroba said:

    We need to establish what the limiting factor is first

    Materials are 55000 kg and labour is 20000h

    The Jackal takes 1 h to produce (6/6=1)
    5000 units x 1h=5000h

    Hyena take 2h (12/6=2), therefore 10000x2=20000h

    The total hours required is 25000h

    This is the limiting factor, so the contribution per limited factor is

    For J 7/1h=7
    Fir H 9/2h=4.5

    Optimal units that can be produced will be

    All of J as it has the highest contribution per limited factor, so 5000 units and whatever is left for H

    5000 will take 5000h, so we have left 15000h/2h =7500 units of Hyena

    @dumutroba quick question why is it 10000 x 2 when Hyena sales demand is 11000?
  • dumutrobadumutroba AAT Student, AATQB Posts: 265
    Misspelled. Is 11000x2h
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  • sophie_612sophie_612 LondonRegistered Posts: 102
    edited July 10
    dumutroba said:

    Misspelled. Is 11000x2h

    @dumutroba thank you
  • dumutrobadumutroba AAT Student, AATQB Posts: 265
    edited July 10
    We only have 20000h available
    You are welcome
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