ACCA F9 text

mark057
mark057 Registered Posts: 352 Dedicated contributor 🦉
edited 11:35AM in AAT member discussion
Hi,

I've just received my text book for ACCA F9 and it looks a fair bit chunkier than the other papers I've
sat.

Has anyone else sat F9. What is it like? Any tips?

Mark

Comments

  • jenny3549
    jenny3549 Registered Posts: 464 Dedicated contributor 🦉
    Don't tell me they get bigger!!! Received my F6 text book this week and can barely lift it - if I drop this I could cause serious damage to anything underneath. If F9 is even heavier I may need to start weightlifting now in preparation.....
  • Rozzi Rainbow
    Rozzi Rainbow Registered Posts: 462 Dedicated contributor 🦉
    Hi Mark

    I ended up quite enjoying F9, and think I might take the advanced version at the professional level. There are lots of tricky calculations in there so the key is practice, practice, practice! Which learning provider's books are you using? In my BPP book it gave a list of formulae you had to learn and a list which will be provided in the exam - but you still need to learn how to apply them. I would suggest don't be put off if at first you don't seem to grasp it, keep going with lots of practice and it should start to come together!
  • mark057
    mark057 Registered Posts: 352 Dedicated contributor 🦉
    Hi Rozzi,

    I've been looking at the maths formulae given in the exam paper.

    Are there many other formulas apart from those?

    Mark
  • Rozzi Rainbow
    Rozzi Rainbow Registered Posts: 462 Dedicated contributor 🦉
    Yes, only some of the formuale are given in the exam paper, there are lots more you are expected to learn - from memory I think it's about half that are provided. Good luck, hope you can enjoy it somewhat.
  • mark057
    mark057 Registered Posts: 352 Dedicated contributor 🦉
    Just a quick query about Miller-Orr calculation on F9.

    Basically how the hell do you calculate the spread?

    I have been trying to calculate an example but can't get it to work out.

    The calculation looks like this 3 x (3/4 x 50 x 4 000 000/0.00025) 1/3

    The answer is supposed to be $25 303.

    My main problem is calculating the bracketed calculation as I don't understand the figure my scientific
    calculator is giving me.

    Any help would be great.

    Mark
  • messedup89
    messedup89 Registered Posts: 1,275 Beyond epic contributor 🧙‍♂️
    Hi mark, are you multiplying the answer you get in the bracket to the power of 1/3? and then multiply that by 3? it should give you the answer

    i my calc i do:
    3/4 = ? x 50 = ? x (4000000/0.00025) = ? to the power of (1/3) = ? x 3 = 25,302.97996
  • mark057
    mark057 Registered Posts: 352 Dedicated contributor 🦉
    Many many thanks for the explanation Messedup. I've managed to calculate it. I'm very grateful.

    Mark

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