this equation
exam panic
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Hi any one here can show me the way to solve this equation please.
2(2x+1)3(x1)=8 I got answer to 3x+1=10 so x=3 really helpful if you guys can solve it for me.
2(2x+1)3(x1)=8 I got answer to 3x+1=10 so x=3 really helpful if you guys can solve it for me.
0
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2(2x+2)3(x1)=8
4x+43x+3=8 (3*1=+3)
rearranging, (so that I can see what I've done):
4x3x+4+3=8
x+7=8
x=87
x=1
hope that makes sense
substitute x=1 into equation to confirm:
4+43+3=8, which is correct0 
I got this (4x+2)+(3x+3)=8 but i don't know why  between brackets changes to + and now you have 4x3x+2+3=8 so that 1x+5=8 so x=85=3 if you put x=3 in equation you have (12+2)(9+3)=8 sorry equation was wrong when i put in the first time . it's 2(2x+1)3(x1)=80

The first part of the equation:
2(2x+2)
the 2 outside of the brackets has to be multipied by both parts inside the brackets so:
2*2x + 2*2
ie 4x+4
similarly in the 2nd part, you have to multiply both the x and 1 by 3
3(x1)
=3*x and 3*1
=3x + 3
(a minus multiplied by a minus gives a positive answer)0 
I got it now thank you so much0

No probs0

Are you happy solving the equation, now that you've amended it?0

just checked and yes, x=3 is the correct answer0
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